folletrap

again not sure: pp35 of the small book: resolving actions: [...] The player begins announcing what Action the model is taking... So: player declares the action and model spend AP...usually tose concide. but with obey the two things split. (player of) zoraida declares the action by obey, the target performs it

not sure: the Obeying model is declaring the action, not the one being obeyed, which happens to be the one Bewitched, so the target of the obey is not making a declaration to trigger the card draw in fact while under obey you don't spend your AP...and you don't spend AP because you don't declare (IMO) IMO bewitch is more a "control" action: it's thinked to reduces the opponent's choices not to make you draw all your deck . But maybe I'm wrong

Wyrdos I need your help to resolve a doubt that emerged yesterday while gaming. Zoraida vs Seamus (great game btw ) Zoraide used "Bewitch" on a model and the use "Obey" on the same model. Is Zoraida allowed to draw 2 cards by bewitch? The doubt borns because Bewitch says that the model must "declare..." but with obey the model doesn't declare action Here the rules: Obey: target non-leader model immediately performs one (1) Action chosen and controlled by this model controller. A model which performed an Attack due to Obey may not be targeted by Obey again duiring the same activation. Bewitch: target enemy model gains the following condition until the end of it's next activation: "Bewitched: Every time this model declares a Walk, Charge or Attack Action wich was not generated by a Charge, the model which applied this condition may draw two cards"